Evaluate the following limit : lim(x→π/2) (1 - sin x)/(π/2 - x)^2 - Sarthaks eConnect | Largest Online Education Community
![calculus - Show that $\int_{0}^{2\pi} \cos^2(x) dx = \int_{0}^{2\pi} \sin^2( x) dx$ - Mathematics Stack Exchange calculus - Show that $\int_{0}^{2\pi} \cos^2(x) dx = \int_{0}^{2\pi} \sin^2( x) dx$ - Mathematics Stack Exchange](https://i.stack.imgur.com/3DCNN.jpg)
calculus - Show that $\int_{0}^{2\pi} \cos^2(x) dx = \int_{0}^{2\pi} \sin^2( x) dx$ - Mathematics Stack Exchange
![Consider a function f (x) in [0,2pi] defined as : f(x)=[{:([sinx]+ [cos x],,, 0 le x le pi),( [sin x] -[cos x],,, pi lt x le 2pi):} where {.} denotes greatest integer Consider a function f (x) in [0,2pi] defined as : f(x)=[{:([sinx]+ [cos x],,, 0 le x le pi),( [sin x] -[cos x],,, pi lt x le 2pi):} where {.} denotes greatest integer](https://d10lpgp6xz60nq.cloudfront.net/web-thumb/135899320_web.png)
Consider a function f (x) in [0,2pi] defined as : f(x)=[{:([sinx]+ [cos x],,, 0 le x le pi),( [sin x] -[cos x],,, pi lt x le 2pi):} where {.} denotes greatest integer
![Basic Trig Identities sin^2 (x) + cos ^2 (x) = 1 sin(-x) = -sin(x), cos(-x) = cos(x), tan(-x) = -tan(x) sin(x + 2Pi) = sin(x), cos(x + 2*Pi) = cos(x), - ppt download Basic Trig Identities sin^2 (x) + cos ^2 (x) = 1 sin(-x) = -sin(x), cos(-x) = cos(x), tan(-x) = -tan(x) sin(x + 2Pi) = sin(x), cos(x + 2*Pi) = cos(x), - ppt download](https://slideplayer.com/6879554/23/images/slide_1.jpg)