![If f(x)=cos[pi/x] cos(pi/2(x-1)) ; where [x] is the greatest integer function of x,then f(x) is continuous at : If f(x)=cos[pi/x] cos(pi/2(x-1)) ; where [x] is the greatest integer function of x,then f(x) is continuous at :](https://d10lpgp6xz60nq.cloudfront.net/ss/web/51560.jpg)
If f(x)=cos[pi/x] cos(pi/2(x-1)) ; where [x] is the greatest integer function of x,then f(x) is continuous at :
Sketch the graphs of the following trigonometric functions: (i) f (x) = cos (x – π/4) (ii) g (x) = cos (x + π/4) (iii) h (x) = cos^2 2x - Sarthaks eConnect | Largest Online Education Community
![If f (x) = cos [ pi ^ 2 ] x + cos [ - pi ^ 2 ] x where. [ . ] stands for the greatest integer function then which of the following is wrong. If f (x) = cos [ pi ^ 2 ] x + cos [ - pi ^ 2 ] x where. [ . ] stands for the greatest integer function then which of the following is wrong.](https://haygot.s3.amazonaws.com/questions/1983248_1180018_ans_5d401a30a76a471092f1bd3d399a3b3d.jpg)
If f (x) = cos [ pi ^ 2 ] x + cos [ - pi ^ 2 ] x where. [ . ] stands for the greatest integer function then which of the following is wrong.
![real analysis - Prove that, $\cos x\ge1-{2x\over\pi}\ \forall x\in[0,{\pi\over2}]$ - Mathematics Stack Exchange real analysis - Prove that, $\cos x\ge1-{2x\over\pi}\ \forall x\in[0,{\pi\over2}]$ - Mathematics Stack Exchange](https://i.stack.imgur.com/wunIp.png)
real analysis - Prove that, $\cos x\ge1-{2x\over\pi}\ \forall x\in[0,{\pi\over2}]$ - Mathematics Stack Exchange
![If f (x) = cos [ pi ^ 2 ] x + cos [ - pi ^ 2 ] x where. [ . ] stands for the greatest integer function then which of the following is wrong. If f (x) = cos [ pi ^ 2 ] x + cos [ - pi ^ 2 ] x where. [ . ] stands for the greatest integer function then which of the following is wrong.](https://haygot.s3.amazonaws.com/questions/1775744_1132743_ans_307c152a00c246d3901f18ffdd316646.jpeg)